document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1002868>Question 1002868</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the length of the radius of a circle with center at the origin and a point on the circle at (-5,-6)? show solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #619734 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=619734\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "Using the distance Formula:<BR>\n" );
document.write( "Sqrt (x2 - x1)^2 + (y2 - y1)^2<BR>\n" );
document.write( "Origin (0,0)<BR>\n" );
document.write( "Point on circle (-5,-6)<BR>\n" );
document.write( "Sqrt (-5 - 0)^2 + (-6 - 0)^2<BR>\n" );
document.write( "Sqrt 25 + 36<BR>\n" );
document.write( "Sqrt 61<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );