document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1002863>Question 1002863</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the distance between C(3,-4) and D(2,b) is 5sqrt2, what is a possible value of b? show solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #619730 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=619730\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "Distance Formula:<BR>\n" );
document.write( "Sqrt (x2 - x1)^2+ (y2 - y1)^2<BR>\n" );
document.write( "Sqrt (2 - 1)^2 + (b - (-4))^2<BR>\n" );
document.write( "Sqrt (1)^2 + (b + 4)^2<BR>\n" );
document.write( "Sqrt (1)^2 + (b + 4)^2 = 5sqrt2<BR>\n" );
document.write( "Sqrt (1)^2 + (b + 4)^2 = sqrt 50<BR>\n" );
document.write( "Square both sides<BR>\n" );
document.write( "1 + (b + 4)^2 = 50<BR>\n" );
document.write( "(b + 4)^2 = 49<BR>\n" );
document.write( "Square root both sides<BR>\n" );
document.write( "b + 4 = 7<BR>\n" );
document.write( "b = 3<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );