document.write( "Question 1002835: Hi, \r
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document.write( "I would just like to say thank you in advanced for your help. My question is as follows: \r
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document.write( "If I lend my money at 6% simple interest for a given time, I shall receive $720 interest but if I lend it for 3 years longer I shall receive $1800 interest. Find the amount of money and time.\r
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document.write( "Thank you again \n" );
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Algebra.Com's Answer #619728 by mananth(16946)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "Let the amount you lend be x\r \n" ); document.write( "\n" ); document.write( "6% foy y years\r \n" ); document.write( "\n" ); document.write( "interest = 0.06 *x*y=720 \n" ); document.write( "xy = 720/0.06 \n" ); document.write( "xy = 12000.................(1)\r \n" ); document.write( "\n" ); document.write( "3 years longer\r \n" ); document.write( "\n" ); document.write( "Amount = x \n" ); document.write( "time = (y+3) years \n" ); document.write( "rate = 6%\r \n" ); document.write( "\n" ); document.write( "1800 = x*(y+3)*0.06\r \n" ); document.write( "\n" ); document.write( "1800 = (xy+3x)*0.06\r \n" ); document.write( "\n" ); document.write( "1800/0.06= xy+3x\r \n" ); document.write( "\n" ); document.write( "30000 = xy+3x...................(2) \n" ); document.write( "plug xy\r \n" ); document.write( "\n" ); document.write( "30000-12000=3x\r \n" ); document.write( "\n" ); document.write( "18000 = 3x\r \n" ); document.write( "\n" ); document.write( "x=6000 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |