document.write( "Question 1002847: how can I solve this equation:
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document.write( " 10^-3+25^1/2-8^1/3•4^1/2+27^0 \n" );
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Algebra.Com's Answer #619719 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "Take each component separately: \n" ); document.write( "10^-3 \n" ); document.write( "= 1/10^3 \n" ); document.write( "= 1/1000 \n" ); document.write( "...... \n" ); document.write( "25^1/2 \n" ); document.write( "= sqrt of 25 \n" ); document.write( "= 5 \n" ); document.write( "...... \n" ); document.write( "8^1/3 \n" ); document.write( "= Cube root of 8 \n" ); document.write( "= 2 \n" ); document.write( ".....4^1/2 \n" ); document.write( "= sqrt of 4 \n" ); document.write( "= 2 \n" ); document.write( "...... \n" ); document.write( "27^0 \n" ); document.write( "Antyhing to the power of 0 \n" ); document.write( "= 1 \n" ); document.write( ".......... \n" ); document.write( "10^-3+25^1/2-8^1/3•4^1/2+27^0\r \n" ); document.write( "\n" ); document.write( "= 1/1000 + 5 - 2 x 2 + 1 \n" ); document.write( "= 3 1/100 x 3 \n" ); document.write( "=9.003 \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |