document.write( "Question 1002847: how can I solve this equation:
\n" ); document.write( " 10^-3+25^1/2-8^1/3•4^1/2+27^0
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Algebra.Com's Answer #619719 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Hi there,
\n" ); document.write( "Take each component separately:
\n" ); document.write( "10^-3
\n" ); document.write( "= 1/10^3
\n" ); document.write( "= 1/1000
\n" ); document.write( "......
\n" ); document.write( "25^1/2
\n" ); document.write( "= sqrt of 25
\n" ); document.write( "= 5
\n" ); document.write( "......
\n" ); document.write( "8^1/3
\n" ); document.write( "= Cube root of 8
\n" ); document.write( "= 2
\n" ); document.write( ".....4^1/2
\n" ); document.write( "= sqrt of 4
\n" ); document.write( "= 2
\n" ); document.write( "......
\n" ); document.write( "27^0
\n" ); document.write( "Antyhing to the power of 0
\n" ); document.write( "= 1
\n" ); document.write( "..........
\n" ); document.write( "10^-3+25^1/2-8^1/3•4^1/2+27^0\r
\n" ); document.write( "\n" ); document.write( "= 1/1000 + 5 - 2 x 2 + 1
\n" ); document.write( "= 3 1/100 x 3
\n" ); document.write( "=9.003
\n" ); document.write( "Hope this helps :-)
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