document.write( "Question 1002843: Xavier drove from his house to the country in 3 hours. Driving at a speed of 12 mph less than on the trip out, he spent 4 hours on the return trip. What was his average rate on the return trip?
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Algebra.Com's Answer #619711 by josgarithmetic(39626)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "             rate       time     distance\r\n" );
document.write( "GOING          r         3        d\r\n" );
document.write( "RETURN        r-12       4        d\r\n" );
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\n" ); document.write( "The question asks for the rate for the RETURN trip. The variables can be
\n" ); document.write( "reassigned this way:\r
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document.write( "             rate       time     distance\r\n" );
document.write( "GOING         r+12       3        d\r\n" );
document.write( "RETURN        r          4        d\r\n" );
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\n" ); document.write( "The new assigning for the rates still keeps the return rate as 12 mph less than the going-to rate.\r
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\n" ); document.write( "\n" ); document.write( "\"3r%2B36=4r\"
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