document.write( "Question 1002775: Please help me solve this: In 2004, the median yearly family income was about $44,000 per year. Suppose the average annual rate of change since then is $1240 per year. Write and graph an equality for the annual family incomes y that are less than the median for x years after 2004. \n" ); document.write( "

Algebra.Com's Answer #619688 by josmiceli(19441) $\"\"$ $\"About$

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Plot median yearly family income, $\"+I+\"$ on the vertical axis
\n" ); document.write( "Plot $\"+x+\"$ years following 2004 on the horizontal axis
\n" ); document.write( " $\"+1240+\"$ is the slope
\n" ); document.write( "The intercept on the vertical axis is $\"+44000+\"$
\n" ); document.write( "--------------------
\n" ); document.write( " $\"+I+=+1240x+%2B+44000+\"$
\n" ); document.write( "--------------------
\n" ); document.write( "If you want to express $\"+I+\"$ as incomes less than
\n" ); document.write( "the median for $\"+x+\"$ years after 2004, you
\n" ); document.write( "need the inequaity:
\n" ); document.write( " $\"+I+%3C+1240x+%2B+44000+\"$ \n" ); document.write( "

\n" );