document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1002744>Question 1002744</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 5 ft longer than twice the width, if the perimeter is 58 ft, find the length and width of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #619622 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=619622\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call length and width, L and W.<BR>\n" );
document.write( "P = 2L + 2W = 58<BR>\n" );
document.write( "and<BR>\n" );
document.write( "L = 5 + 2W<BR>\n" );
document.write( "Substitute this into the first equation and get<BR>\n" );
document.write( "2(5+2W) + 2W = 58<BR>\n" );
document.write( "10 + 4W + 2W = 58<BR>\n" );
document.write( "6W + 10 = 58<BR>\n" );
document.write( "6W = 48<BR>\n" );
document.write( "W = 8 ft<BR>\n" );
document.write( "L = 21 ft </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );