document.write( "Question 85735: If the given values in a right triangle are Cos A = 1/3 and a=2, find the
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Algebra.Com's Answer #61957 by Edwin McCravy(20055)\"\" \"About 
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If the given values in a right triangle are Cos A = 1/3 and a=2,\r\n" );
document.write( "find the hypotenuse c.\r\n" );
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document.write( "We have the system of equations:\r\n" );
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document.write( "\"a%5E2+%2B+b%5E2+=+c%5E2\"\r\n" );
document.write( "\"cos%28A%29+=+1%2F3\"\r\n" );
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document.write( "or\r\n" );
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document.write( "\"2%5E2+%2B+b%5E2+=+c%5E2\"\r\n" );
document.write( "\"b%2Fc+=+1%2F3\"\r\n" );
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document.write( "or\r\n" );
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document.write( "\"4+%2B+b%5E2+=+c%5E2\"\r\n" );
document.write( "\"c+=+3b\"\r\n" );
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document.write( "Now we can use substitution to solve:\r\n" );
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document.write( "\"4+%2B+b%5E2+=+%283b%29%5E2\"\r\n" );
document.write( "\"4+%2B+b%5E2+=+9b%5E2\"\r\n" );
document.write( "\"4+=+8b%5E2\"\r\n" );
document.write( "\"1+=+2b%5E2\"\r\n" );
document.write( "\"1%2F2+=+%282b%5E2%29%2F2\"\r\n" );
document.write( "\"1%2F2+=+b%5E2\"\r\n" );
document.write( "\"sqrt%281%2F2%29+=+sqrt%28b%5E2%29\"\r\n" );
document.write( "\"sqrt%282%2F4%29+=+b\"\r\n" );
document.write( "\"sqrt%282%29%2F2+=+b\"\r\n" );
document.write( "Substitute that in \"c=3b\"\r\n" );
document.write( "\"c=%283sqrt%282%29%29%2F2\"\r\n" );
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document.write( "Edwin
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