document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1002650>Question 1002650</A>: <I><SPAN STYLE=\"word-break: break-all;\"> there are 3 consecutive integers  that have a sum of 51. which inegers are they\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #619515 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=619515\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call them x, x+1, and x+2.  They sum to 51, so we write<BR>\n" );
document.write( "x+(x+1)+(x+2)=51<BR>\n" );
document.write( "3x+3=51<BR>\n" );
document.write( "3x = 48<BR>\n" );
document.write( "x = 16<BR>\n" );
document.write( "The numbers are 16, 17 and 18. </SPAN>\n" );
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