document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1002638>Question 1002638</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the substitution solution to x+y=3 and y=x+3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #619512 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52786)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=619512\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "You just have y expressed via &nbsp;x&nbsp; from the 2nd equation, &nbsp;y = x + 3.<BR>\n" );
document.write( "Substitute it into the first equation. &nbsp;You will get \r<BR>\n" );
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document.write( "x + (x+3) = 3.\r<BR>\n" );
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document.write( "Hence, &nbsp;2x = 0, x = 0.\r<BR>\n" );
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document.write( "Then &nbsp;y = x+3 = 0+3 = 3.\r<BR>\n" );
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document.write( "<U>Answer</U>. &nbsp;x = 0, y = 3.\r<BR>\n" );
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