document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1002545>Question 1002545</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the 3sides of a triangle is 10(2/3)cm.if two of the sides measure 2(3/4)cm and 4(1/2)cm.find the length of the third side? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #619463 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=619463\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "First add your two sides:<BR>\n" );
document.write( "2 (3/4) + 4 (1/2)<BR>\n" );
document.write( "= 11/4 + 9/2<BR>\n" );
document.write( "= 29/4<BR>\n" );
document.write( "Next subtract the answer from the total:<BR>\n" );
document.write( "10 (2/3) - 29/4<BR>\n" );
document.write( "32/3 - 29/4<BR>\n" );
document.write( "= 128 - 87/12<BR>\n" );
document.write( "= 41/12<BR>\n" );
document.write( "= 3 (5/12) The third side<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );