document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1002516>Question 1002516</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A jeweler is commissioned to create a piece that will weigh 14oz. And consist of 75% gold. Two alloys are available that are 60% and 80% gold respectively. How much of each alloy should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #619413 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=619413\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A jeweler is commissioned to create a piece that will weigh 14oz. And consist of 75% gold. Two alloys are available that are 60% and 80% gold respectively. How much of each alloy should be used?<BR>\n" );
document.write( "let x= amt of 60% alloy used<BR>\n" );
document.write( "14-x= amt of 80% alloy used<BR>\n" );
document.write( "60%x+80%(14-x)=75%*14<BR>\n" );
document.write( ".60x+11.2-.80x=10.5<BR>\n" );
document.write( ".2x=.70<BR>\n" );
document.write( "x=3.5<BR>\n" );
document.write( "14-x=10.5<BR>\n" );
document.write( " amt of60% alloy used=3.5 oz<BR>\n" );
document.write( " amt of 80% alloy used=10.5 oz </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );