document.write( "Question 1002518: A rectangle corner lot has a width 12 feet less than its length. When three feet are taken from one width and one length, to be used as a sidewalk, the area of the lots is reduced by 177ft(2). Find the original dimensions of the lot. \n" ); document.write( "
Algebra.Com's Answer #619412 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
This sidewalk is only going half-way around, and will not be a perimeter border.\r
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\n" ); document.write( "\n" ); document.write( "L for lot length
\n" ); document.write( "w for lot width
\n" ); document.write( "-
\n" ); document.write( "\"w=L-12\"
\n" ); document.write( "Total Lot, \"w%2AL\" square feet
\n" ); document.write( "Reduced Lot, \"%28w-3%29%28L-3%29\"
\n" ); document.write( "Sidewalk area is the total lot area minus the reduced lot area.
\n" ); document.write( "\"wL-%28w-3%29%28L-3%29=177\"---first, simplify this.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"wL-%28wL-3L-3w%2B9%29=177\"
\n" ); document.write( "\"wL-wL%2B3L%2B3w-9=177\"
\n" ); document.write( "\"3L%2B3w-9-177=0\"
\n" ); document.write( "\"3L%2B3w-186=0\"
\n" ); document.write( "Substitute for w, from the description fact.
\n" ); document.write( "\"3L%2B3%28L-12%29-186=0\"
\n" ); document.write( "\"3L%2B3L-36-186=0\"
\n" ); document.write( "\"6L=186%2B36\"
\n" ); document.write( "\"6L=222\"
\n" ); document.write( "\"highlight%28L=37%29\" and from this find that \"highlight%28w=25%29\".
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