document.write( "Question 1002532: When workers A and B work together, they can finish the flooring of a house in 6 days.When worker A works alone, he takes 5 days less than worker B to finish the flooring of the house. How many days does worker A and worker B needs to finish the flooring of the house if they work alone? \n" ); document.write( "
Algebra.Com's Answer #619404 by stanbon(75887)\"\" \"About 
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When workers A and B work together, they can finish the flooring of a house in 6 days.When worker A works alone, he takes 5 days less than worker B to finish the flooring of the house. How many days does worker A and worker B needs to finish the flooring of the house if they work alone?
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\n" ); document.write( "Together rate:: 1/6 job/day
\n" ); document.write( "Worker B rate:: 1/x job/day
\n" ); document.write( "Worker A rate:: 1/(x-5) job/day
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\n" ); document.write( "Equation:
\n" ); document.write( "rate + rate = together rate
\n" ); document.write( "1/x + 1/(x-5) = 1/6
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\n" ); document.write( "6(x-5) + 6x = x(x-5)
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\n" ); document.write( "12x - 30 = x^2 - 5x
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\n" ); document.write( "x^2 -17x + 30 = 0
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\n" ); document.write( "(x-15)(x-2) = 0
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\n" ); document.write( "Realistic answer:
\n" ); document.write( "x = 15
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\n" ); document.write( "B time = x = 15 days to do the job alone
\n" ); document.write( "A time = x-5 = 10 days to do the job alone
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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