document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1002503>Question 1002503</A>: <I><SPAN STYLE=\"word-break: break-all;\">  \r<BR>\n" );
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document.write( " Jim travels <BR>\n" );
document.write( "6 times faster than Brenda.  Traveling in opposite directions, they are <BR>\n" );
document.write( "392 miles apart after <BR>\n" );
document.write( "3.5 hours.  Find their rates of travel.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #619387 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=619387\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Jim travels 6 times faster than Brenda.  Traveling in opposite directions, they are 392 miles apart after 3.5 hours.  Find their rates of travel.<BR>\n" );
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document.write( "The combined speed is 392/3.5 = 112 mi/hr<BR>\n" );
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document.write( "J + B = 112 mi/hr<BR>\n" );
document.write( "J = 7B<BR>\n" );
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document.write( "7B + B = 112<BR>\n" );
document.write( "B = 14 mi/hr (Brenda's speed)<BR>\n" );
document.write( "J = 98 mi/hr (Jim's speed)<BR>\n" );
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document.write( "PS  6 times faster is not 6 times as fast, it's 7 times as fast.<BR>\n" );
document.write( "6 times faster --> a 600% increase<BR>\n" );
document.write( "A 100% increase = 2 times as fast.<BR>\n" );
document.write( "200% --> 3 times as fast, etc.<BR>\n" );
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