document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1002461>Question 1002461</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4x-2y+Z=-7<BR>\n" );
document.write( "Y+2z=1<BR>\n" );
document.write( "Z=-1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #619369 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=619369\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You substitute the third into the second equation, then into the first...<BR>\n" );
document.write( "y+2(-1)=1<BR>\n" );
document.write( "y-2=1<BR>\n" );
document.write( "y = 3<BR>\n" );
document.write( "Then<BR>\n" );
document.write( "4x-2(3)+(-1) = -7<BR>\n" );
document.write( "4x -6 -1 = -7<BR>\n" );
document.write( "4x = 0<BR>\n" );
document.write( "x = 0<BR>\n" );
document.write( "(0,3,-1) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );