document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1002464>Question 1002464</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3ln(x-1)+4=10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #619366 by </B><A HREF=/tutors/aboutme.mpl?userid=person24><B>person24(13)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=person24><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=619366\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3ln(x-1)+4=10\r<BR>\n" );
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document.write( "first we want to get the natural log all by itself<BR>\n" );
document.write( "subtract 4 from both sides\r<BR>\n" );
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document.write( "3ln(x-1)=6\r<BR>\n" );
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document.write( "now lets divide 3 by both sides\r<BR>\n" );
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document.write( "ln(x-1)=2\r<BR>\n" );
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document.write( "now we can take the anti-log of both sides\r<BR>\n" );
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document.write( "x-1=e^2\r<BR>\n" );
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document.write( "Now add one to both sides\r<BR>\n" );
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document.write( "x=e^2+1\r<BR>\n" );
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document.write( "Hope that helps!!! </SPAN>\n" );
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