document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1002456>Question 1002456</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Measure of the larger of two complementary angles is 12° more than five times the measure of the smaller angle. what are the angle measures?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #619358 by </B><A HREF=/tutors/aboutme.mpl?userid=person24><B>person24(13)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=person24><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=619358\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First put it in a equation. Since complementary means two angles that add up to 90 degrees. a+b=90 degrees. <BR>\n" );
document.write( "We know that larger angle (b) is 5 times lager than A. <BR>\n" );
document.write( "So write <BR>\n" );
document.write( "5A. <BR>\n" );
document.write( "We also know that is added by 12. <BR>\n" );
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document.write( "5A+12=B.\r<BR>\n" );
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document.write( "Now lets subsitue b for 5A+12..... \r<BR>\n" );
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document.write( "5A+12+A=90 degress\r<BR>\n" );
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document.write( "Solve for A\r<BR>\n" );
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document.write( "6A+12=90\r<BR>\n" );
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document.write( "Subtract 12\r<BR>\n" );
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document.write( "6A=90\r<BR>\n" );
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document.write( "Divide by 6\r<BR>\n" );
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document.write( "A=15\r<BR>\n" );
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document.write( "Solve for B by plugging A into the original equation A+B=90\r<BR>\n" );
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document.write( "15+B=90\r<BR>\n" );
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document.write( "Subtract 15\r<BR>\n" );
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document.write( "B=75\r<BR>\n" );
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document.write( "Hope that helps!\r<BR>\n" );
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document.write( " </SPAN>\n" );
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