document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1002414>Question 1002414</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You've invested $9000 between two accounts paying 7% and 9% annual interest. If the total interest earned for the year was $730, how much was invested at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #619335 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=619335\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You've invested $9000 between two accounts paying 7% and 9% annual interest. If the total interest earned for the year was $730, how much was invested at each rate?<BR>\n" );
document.write( "let x=amt invested at the 7% interest rate<BR>\n" );
document.write( "9000-x=amt invested at the 9% interest rate<BR>\n" );
document.write( ".07x+.09(9000-x=730<BR>\n" );
document.write( ".07x+810-.09x=730<BR>\n" );
document.write( ".02x=80<BR>\n" );
document.write( "x=4000<BR>\n" );
document.write( "9000-x=5000<BR>\n" );
document.write( "amt invested at the 7% interest rate=$4000<BR>\n" );
document.write( "amt invested at the 9% interest rate=$5000 </SPAN>\n" );
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