document.write( "Question 1002354: A jet plane traveling at 500 mph overtakes a propeller plane traveling at 200 mph that had a 2-hour head start. How far from the starting point are the planes?
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Algebra.Com's Answer #619286 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! Call the time the faster plane flies, t hours. \n" ); document.write( "The slower plane, then, has flown t+2 hours, when they meet. \n" ); document.write( "Since their distance are equal, their rates times times are equal (d=rt)...so \n" ); document.write( "500t = 200(t+2) \n" ); document.write( "500t = 200t + 400 \n" ); document.write( "300t = 400 \n" ); document.write( "t = 4/3 hours \n" ); document.write( "500(4/3) = 2000/3 miles = 666 2/3 miles \n" ); document.write( " |