document.write( "Question 1002345: Over the last three evenings, Heather received a total of
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document.write( "109
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document.write( " phone calls at the call center. The third evening, she received
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document.write( "4
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document.write( " times as many calls as the second evening. The first evening, she received
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document.write( "7
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document.write( " more calls than the second evening. How many phone calls did she receive each evening? \n" );
document.write( "
Algebra.Com's Answer #619275 by stanbon(75887) ![]() You can put this solution on YOUR website! Over the last three evenings, Heather received a total of \n" ); document.write( "109 \n" ); document.write( "phone calls at the call center. The third evening, she received \n" ); document.write( "4 \n" ); document.write( "times as many calls as the second evening. The first evening, she received \n" ); document.write( "7 \n" ); document.write( "more calls than the second evening. How many phone calls did she receive each evening? \n" ); document.write( "--------- \n" ); document.write( "Let the # of calls per evening be a,b,c:: \n" ); document.write( "----- \n" ); document.write( "Equations: \n" ); document.write( "a + b + c = 109 \n" ); document.write( "c = 4b \n" ); document.write( "a = b + 7 \n" ); document.write( "----- \n" ); document.write( "Substitute for a and c and solve for \"b\": \n" ); document.write( "b+7 + b + 4b = 109 \n" ); document.write( "6b = 102 \n" ); document.write( "b = 17 (# of calls on the 2nd evening) \n" ); document.write( "--- \n" ); document.write( "a = b+7 = 24 (# of calls on the 1st evening) \n" ); document.write( "---- \n" ); document.write( "c = 4b = 4*17 = 68 (# of calls on the 3rd evening) \n" ); document.write( "--------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------- \n" ); document.write( "---- \n" ); document.write( " |