document.write( "Question 1002171: A radio active isotope decays according to the exponential decay equation where t is in days.\r
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document.write( "Round to the thousandths place.\r
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document.write( "For the half life: The half life is the solution (t) of the equation : a2=ae^−6.345t
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Algebra.Com's Answer #619230 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "a2=ae^−6.345t \n" ); document.write( "Make A2 = 1 \n" ); document.write( "A = 1 \n" ); document.write( "a2=ae^−6.345t \n" ); document.write( "1 = 2e^-6.345t \n" ); document.write( "1/2 = e^-6345t \n" ); document.write( "0.5 = e^-6.345t \n" ); document.write( "ln0.5 = -6.345t lne (lne = 1) \n" ); document.write( "ln0.5 = -6.345t \n" ); document.write( "t = ln0.5/-6.345 \n" ); document.write( "t = 0.109 of a day. \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |