document.write( "Question 1002171: A radio active isotope decays according to the exponential decay equation where t is in days.\r
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\n" ); document.write( "\n" ); document.write( "For the half life: The half life is the solution (t) of the equation : a2=ae^−6.345t
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Algebra.Com's Answer #619230 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Hi there,
\n" ); document.write( "a2=ae^−6.345t
\n" ); document.write( "Make A2 = 1
\n" ); document.write( "A = 1
\n" ); document.write( "a2=ae^−6.345t
\n" ); document.write( "1 = 2e^-6.345t
\n" ); document.write( "1/2 = e^-6345t
\n" ); document.write( "0.5 = e^-6.345t
\n" ); document.write( "ln0.5 = -6.345t lne (lne = 1)
\n" ); document.write( "ln0.5 = -6.345t
\n" ); document.write( "t = ln0.5/-6.345
\n" ); document.write( "t = 0.109 of a day.
\n" ); document.write( "Hope this helps :-)
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