document.write( "Question 1002262: Two cards are drawn without replacement from the ordinary
\n" ); document.write( "deck, find the probability that the second is not a face
\n" ); document.write( "card given that the first is a face card. \n" ); document.write( "

Algebra.Com's Answer #619223 by Edwin McCravy(20060) $\"\"$ $\"About$

You can put this solution on YOUR website!
Two cards are drawn without replacement from the ordinary
\n" ); document.write( "deck, find the probability that the second is not a face
\n" ); document.write( "card given that the first is a face card.
\n" ); document.write( "

\r\n" );
document.write( "\r\n" );
document.write( "A deck of 52 cards contains 12 face cards, and 40 non-face \r\n" );
document.write( "cards. \r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( " \r\n" );
document.write( "A♥   2♥   3♥   4♥   5♥   6♥   7♥   8♥  9♥  10♥  J♥  Q♥  K♥ \r\n" );
document.write( "A♦   2♦   3♦   4♦   5♦   6♦   7♦   8♦  9♦  10♦  J♦  Q♦  K♦\r\n" );
document.write( "A♠   2♠   3♠   4♠   5♠   6♠   7♠   8♠  9♠  10♠  J♠  Q♠  K♠  \r\n" );
document.write( "A♣   2♣   3♣   4♣   5♣   6♣   7♣   8♣  9♣  10♣  J♣  Q♣  K♣ \r\n" );
document.write( "\r\n" );
document.write( "Since we are given that the first card has been drawn and it was a\r\n" );
document.write( "face card and we are not going to replace it before drawing a second\r\n" );
document.write( "card, then\r\n" );
document.write( "\r\n" );
document.write( "we have a 51-card deck with only 11 face cards and still 40 non-face \r\n" );
document.write( "cards.\r\n" );
document.write( "\r\n" );
document.write( "So the probability is 40 ways out of 51.\r\n" );
document.write( "\r\n" );
document.write( "Answer 40/51\r\n" );
document.write( "\r\n" );
document.write( "Edwin

\n" ); document.write( "

\n" );