document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1002268>Question 1002268</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle has a length 2m less than twice its width. When 3 m are added to the width, the resulting figures is a square with an area of 64 m^2. Find the dimensions of the original rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #619197 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=619197\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a rectangle has a length 2m less than twice its width. When 3 m are added to the width, the resulting figures is a square with an area of 64 m^2. Find the dimensions of the original rectangle\r<BR>\n" );
document.write( "\n" );
document.write( "let x=width<BR>\n" );
document.write( "2x-2=length<BR>\n" );
document.write( "(x+3)^2=x^2+6x+9=64<BR>\n" );
document.write( "x^2+6x-55=0<BR>\n" );
document.write( "(x+11)(x-5)=0<BR>\n" );
document.write( "x=5<BR>\n" );
document.write( "2x-2=8<BR>\n" );
document.write( "dimensions of the original rectangle:<BR>\n" );
document.write( "width=5 m<BR>\n" );
document.write( "length=8 m </SPAN>\n" );
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