document.write( "Question 1002149: The population of a colony of bacteria increases exponentially with time. If the population starts with 8000 bacteria and 4 hours later the population is 10000...\r
\n" ); document.write( "\n" ); document.write( "a.) when will the population be 12000?
\n" ); document.write( "b.) what is the doubling time?
\n" ); document.write( "c.) what will the population be after 10 hours?
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Algebra.Com's Answer #619189 by fractalier(6550)\"\" \"About 
You can put this solution on YOUR website!
In general, exponential growth takes the form
\n" ); document.write( "\"A%28t%29+=+Ao%28e%5E%28kt%29%29\"
\n" ); document.write( "Let's plug in to find k...
\n" ); document.write( "\"10000=8000%2Ae%5E%284k%29\"
\n" ); document.write( "\"1.25+=+e%5E%284k%29\"
\n" ); document.write( "\"ln%281.25%29+=+4k\"
\n" ); document.write( "k = ln(1.25)/4 = .05579
\n" ); document.write( "Now plug that into
\n" ); document.write( "\"A%28t%29+=+Ao%28e%5E%28kt%29%29\" to get
\n" ); document.write( "\"A%28t%29+=+Ao%28e%5E%28.05579%2At%29%29\"
\n" ); document.write( "and for your case
\n" ); document.write( "\"A%28t%29+=+8000%2A%28e%5E%28.05579%2At%29%29\"
\n" ); document.write( "Now plug in 12000 for A(t) to find t for part a,
\n" ); document.write( "plug in 16000 for A(t) to find t for part b,
\n" ); document.write( "and plug in 10 for t to find A(t)for part c.
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