document.write( "Question 1002235: solve each system using the substitution method or the addition method
\n" ); document.write( "x-3/2=2-y/4
\n" ); document.write( "7-2x/3=y/2\r
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Algebra.Com's Answer #619188 by addingup(3677)\"\" \"About 
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x-3/2=2-y/4
\n" ); document.write( "7-2x/3=y/2
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\n" ); document.write( "x-3/2=2-y/4 Multiply both sides by 4:
\n" ); document.write( "4x-6= 8-y Add 6 to both sides:
\n" ); document.write( "4x= 14-y This is the equation we'll use for the addition.
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\n" ); document.write( "7-2x/3=y/2 Subtract 7 from both sides
\n" ); document.write( "-2x/3= -7+y/2 Multiply all sides by 6:
\n" ); document.write( "-4x= -42+3y
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\n" ); document.write( "Now let's add:
\n" ); document.write( "4x= 14-y
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\n" ); document.write( "-4x= -42+3y
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\n" ); document.write( "0x= -28+2y Add 8 on both sides
\n" ); document.write( "28= 2y Divide both sides by 2
\n" ); document.write( "y= 14 and
\n" ); document.write( "14x= 14-y
\n" ); document.write( "14x= 14-14
\n" ); document.write( "14x= 0
\n" ); document.write( "x= 0
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