document.write( "Question 1002234: solve each system using the substitution method or the addition method
\n" ); document.write( "3(2x+y)=4x+20
\n" ); document.write( "x-2y=3\r
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Algebra.Com's Answer #619186 by mananth(16946)\"\" \"About 
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3(2x+y)=4x+20
\n" ); document.write( "6x +3y =4x+20\r
\n" ); document.write( "\n" ); document.write( "2x+3y=20
\n" ); document.write( "x-2y=3\r
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\n" ); document.write( "\n" ); document.write( "2 x + 3.00 y = 20 .............1
\n" ); document.write( "Total value
\n" ); document.write( "1 x -2 y = 3 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by 2
\n" ); document.write( "Multiply (2) by 3.00
\n" ); document.write( "4 x 6 y = 40
\n" ); document.write( "3 x -6 y = 9
\n" ); document.write( "Add the two equations
\n" ); document.write( "7 x = 49
\n" ); document.write( "/ 7
\n" ); document.write( "x = 7
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "2 x + 3 y = 20
\n" ); document.write( "14 + 3 y = 20
\n" ); document.write( " 3 y = 20 -14
\n" ); document.write( " 3 y = 6
\n" ); document.write( " y = 2
\n" ); document.write( "x= 7
\n" ); document.write( "y= 2
\n" ); document.write( "m.ananth@hotmail.ca \r
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