document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1002199>Question 1002199</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I don't understand how to do this problem I have 3 like it please help asap thank you. My instructions say write an equation of the line that passes through point P and is parallel to the line with the given instructions.... P(-3,6), y=-x-5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #619155 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=619155\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The line has slope -1, since it is written in slope-intercept form and x has a (-1) coefficient.<BR>\n" );
document.write( "use point slope formula<BR>\n" );
document.write( "y-y1=(-1)(x-x1)<BR>\n" );
document.write( "y-6=(-1)(x+3)=-x-3<BR>\n" );
document.write( "y=-x+3<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C-x-5%2C-x%2B3%29 ALIGN=MIDDLE  ALT=\"graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C-x-5%2C-x%2B3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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