document.write( "Question 1002199: I don't understand how to do this problem I have 3 like it please help asap thank you. My instructions say write an equation of the line that passes through point P and is parallel to the line with the given instructions.... P(-3,6), y=-x-5 \n" ); document.write( "
Algebra.Com's Answer #619154 by jim_thompson5910(35256)\"\" \"About 
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Given Line: y=-x-5
\n" ); document.write( "That is equivalent to y = -1x-5
\n" ); document.write( "The equation is in the form y = mx+b where the slope is m = -1\r
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\n" ); document.write( "\n" ); document.write( "ANY line parallel to this given line will also have a slope of -1. Since parallel lines have equal slopes.\r
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\n" ); document.write( "\n" ); document.write( "The given point is P(-3,6). All points are of the form (x,y) so x = -3 and y = 6\r
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\n" ); document.write( "\n" ); document.write( "We will plug m = -1, x = -3 and y = 6 into y = mx+b and solve for b\r
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\n" ); document.write( "\n" ); document.write( "y = mx+b
\n" ); document.write( "y = -1x+b ... replace m with -1
\n" ); document.write( "y = -1(-3)+b ... plug in x = -3
\n" ); document.write( "6 = -1(-3)+b ... replace y with 6, solve for b
\n" ); document.write( "6 = 3+b
\n" ); document.write( "6-3 = 3+b-3 ... subtract 3 from both sides to isolate b
\n" ); document.write( "3 = b
\n" ); document.write( "b = 3\r
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\n" ); document.write( "\n" ); document.write( "So we know m = -1 and b = 3 turning y = mx+b into y = -x+3 which is the final answer
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