document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1002191>Question 1002191</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist needs 1000 mL of a solution that is 40% acid. He has one solution that is 10% acid, and a second solution that is 60% acid. How much of each solution should be mixed together? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #619139 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=619139\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist needs 1000 mL of a solution that is 40% acid. He has one solution that is 10% acid, and a second solution that is 60% acid. How much of each solution should be mixed together? <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.10x + 0.60(1000-x) = 0.40*1000<BR>\n" );
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document.write( "10x + 60*1000 - 60x = 40*1000<BR>\n" );
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document.write( "-50x = -10*1000<BR>\n" );
document.write( "x = (1/5)(1000)<BR>\n" );
document.write( "x = 200 ml (amt. of 10% solution needed)<BR>\n" );
document.write( "1000-x = 800 ml (amt. of 40% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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