document.write( "Question 1002133: 5 times Jake's age equals 120 minus 3 times Cindy's age, and 2 times Jake's age plus 3 times Cindy's age equals 66. What is each person's age?
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Algebra.Com's Answer #619112 by stanbon(75887)\"\" \"About 
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5 times Jake's age equals 120 minus 3 times Cindy's age, and 2 times Jake's age plus 3 times Cindy's age equals 66. What is each person's age?
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\n" ); document.write( "Equations:
\n" ); document.write( "5*j = 120-3c
\n" ); document.write( "2j+3c = 66
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\n" ); document.write( "Rearrange:
\n" ); document.write( "5j + 3c = 120
\n" ); document.write( "2j + 3c = 66
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\n" ); document.write( "Subtract and solve for \"j\"::
\n" ); document.write( "3j = 54
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\n" ); document.write( "jake's age = 18 yrs
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\n" ); document.write( "Solve for \"c\":
\n" ); document.write( "2j + 3c = 66
\n" ); document.write( "36 + 3c = 66
\n" ); document.write( "3c = 30
\n" ); document.write( "Cindy's age = 10 yrs.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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