document.write( "Question 1002133: 5 times Jake's age equals 120 minus 3 times Cindy's age, and 2 times Jake's age plus 3 times Cindy's age equals 66. What is each person's age?
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Algebra.Com's Answer #619112 by stanbon(75887) ![]() You can put this solution on YOUR website! 5 times Jake's age equals 120 minus 3 times Cindy's age, and 2 times Jake's age plus 3 times Cindy's age equals 66. What is each person's age? \n" ); document.write( "======= \n" ); document.write( "Equations: \n" ); document.write( "5*j = 120-3c \n" ); document.write( "2j+3c = 66 \n" ); document.write( "-------- \n" ); document.write( "Rearrange: \n" ); document.write( "5j + 3c = 120 \n" ); document.write( "2j + 3c = 66 \n" ); document.write( "---- \n" ); document.write( "Subtract and solve for \"j\":: \n" ); document.write( "3j = 54 \n" ); document.write( "--- \n" ); document.write( "jake's age = 18 yrs \n" ); document.write( "----- \n" ); document.write( "Solve for \"c\": \n" ); document.write( "2j + 3c = 66 \n" ); document.write( "36 + 3c = 66 \n" ); document.write( "3c = 30 \n" ); document.write( "Cindy's age = 10 yrs. \n" ); document.write( "=========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |