document.write( "Question 1002126: A load of 6kg stretches a coil spring to a length of 30cm, and a load of 10kg stretches it to a length of 40cm. Find the length of the spring when there is no load. \n" ); document.write( "
Algebra.Com's Answer #619111 by KMST(5328)\"\" \"About 
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\"x\"= length of the spring when there is no load, in cm.
\n" ); document.write( "\"30-x\"= stretching of the spring with a \"6kg\" load, in cm.
\n" ); document.write( "\"40-x\"= stretching of the spring with a \"10kg\" load, in cm.
\n" ); document.write( "A very high load, will forever deform, or even break a spring.
\n" ); document.write( "However, with reasonable loads, the stretching of a spring is proportional to the load applied, applied, and vice versa.
\n" ); document.write( "In equation form, that proportional relation is:
\n" ); document.write( "Load in kg = K(strecthing in cm) ,
\n" ); document.write( "where K is a constant, i kg/cm.
\n" ); document.write( "Without writing the units, the data we are given shows
\n" ); document.write( "\"6=K%2830-x%29\"
\n" ); document.write( "\"10=K%2840-x%29\"
\n" ); document.write( "dividing one equation by the other, we get
\n" ); document.write( "\"6%2F10=K%2830-x%29%2F%28K%2840-x%29%29\" ---> \"6%2F10=%2830-x%29%2F%2840-x%29\"
\n" ); document.write( "\"6%2840-x%29=10%2830-x%29\"
\n" ); document.write( "\"240-6x=300-10x\"
\n" ); document.write( "\"10x-6x=300-240+\"
\n" ); document.write( "\"4x=60+\" ---> \"x=60%2F4\" ---> \"x=15\" .
\n" ); document.write( "The length of the spring when there is no load is \"highlight%2815cm%29\" .
\n" ); document.write( "
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