document.write( "Question 12229: A person has a basket of fruit, consisting of apples, oranges and bananas. The total pieces of fruit is equal to 80. The number of oranges is 5 more than 1/3 of the number of apples. The number of bananas is 1 less than 1/4 the number of apples. How many of each fruit will you have? \n" ); document.write( "

Algebra.Com's Answer #6191 by kusha(21) $\"\"$ $\"About$

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Let the no. of apples be x, the number of bananas be y and the number of oranges be z.
\n" ); document.write( "then x+y+z = 80 (given total of all these fruits)\r
\n" ); document.write( "\n" ); document.write( "Z = (1/3)x + 5 given in question that oranges are 5 more than one-third of apples\r
\n" ); document.write( "\n" ); document.write( "y = (1/4)x - 1 given in question\r
\n" ); document.write( "\n" ); document.write( "Now we have three equations and consider the ques solved cause in simple equations we can solve as many varibles as are the number of equations e.g.\r
\n" ); document.write( "\n" ); document.write( "here let us substitute the vlue of x & y in original equation.
\n" ); document.write( "x + (1/4)x + 5 + (1/3)x - 1 = 80
\n" ); document.write( "(19/12)x + 4 = 80
\n" ); document.write( "(19/12)x =80-4
\n" ); document.write( "x = 76 x (12/19)
\n" ); document.write( "x = 48 thus no. of apples is 48\r
\n" ); document.write( "\n" ); document.write( "z = (1/3)x + 5 from earliar eqn. thus z =21 hence oranges are 21\r
\n" ); document.write( "\n" ); document.write( "and balance 80 - (48 + 21) = 11 would be bananas
\n" ); document.write( "alternatively we can also find bananas by substituting value of x in the eqn
\n" ); document.write( "y = (1/4)x - 1\r
\n" ); document.write( "\n" ); document.write( "So apples = 48, bananas = 11, oranges = 21 \n" ); document.write( "

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