document.write( "Question 1002096: I have been stuck to this question on my math exam..can you solve this for me?\r
\n" ); document.write( "\n" ); document.write( "Find the dimension of a rectangle with an area of 27 square meters, if the length of a rectangle is three more than twice the width.\r
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Algebra.Com's Answer #619090 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Hi there,
\n" ); document.write( "Make the width = 'x'
\n" ); document.write( "Length = 3 + 2x
\n" ); document.write( "Area of rectangle = Length x width
\n" ); document.write( "27 = (3 + 2x)(x)
\n" ); document.write( "27 = 3x + 2x^2
\n" ); document.write( "2x^2 + 3x - 27 = 0
\n" ); document.write( "Factorise:
\n" ); document.write( "Using Quadratic formula:
\n" ); document.write( "\"x+=+-b%2B-sqrt%28b%5E2-4%2Aa%2Ac%29%29%2F%282a%29\"
\n" ); document.write( "a = 2: b = 3: c = -27:
\n" ); document.write( "\"x+=+%28-3%2B-sqrt%283%5E2-4%2A2%2A-27%29%29%2F%282%2A2%29\"
\n" ); document.write( "\"x+=+%28-3%2B-sqrt%28225%29%29%2F4\"
\n" ); document.write( "[[[x = -3+sqrt(225))/4}}} or [[[x = -3-sqrt(225))/4}}}
\n" ); document.write( "x = 3 or -4.5(Discount as -ve)
\n" ); document.write( "So, Width = 3.0m
\n" ); document.write( "Length = 9.0m
\n" ); document.write( "Hope this helps :-)
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