document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1002068>Question 1002068</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find four consecutive integers such that the sum of the first three is 54 more than the fourth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #619075 by </B><A HREF=/tutors/aboutme.mpl?userid=Timnewman><B>Timnewman(323)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Timnewman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Timnewman><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=619075\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi dear,<BR>\n" );
document.write( "let the interger be x,x+1,x+2,andx+3,.<BR>\n" );
document.write( "since,the sum of the first three is 54 more than the fourth,<BR>\n" );
document.write( "Then,<BR>\n" );
document.write( "x+x+1+x+2=x+3+54<BR>\n" );
document.write( "3x+3=x+57<BR>\n" );
document.write( "2x=57-3<BR>\n" );
document.write( "2x=54<BR>\n" );
document.write( "x=27<BR>\n" );
document.write( "The consecutive intergers are:27,28,29,and 30 <BR>\n" );
document.write( "OR<BR>\n" );
document.write( "-27,-28,-29 and -30<BR>\n" );
document.write( "HOPE THIS HELPS? </SPAN>\n" );
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