document.write( "Question 1002068: Find four consecutive integers such that the sum of the first three is 54 more than the fourth. \n" ); document.write( "
Algebra.Com's Answer #619074 by chipchocolate(1)\"\" \"About 
You can put this solution on YOUR website!
Let x = the first number
\n" ); document.write( "(x+1) = the second
\n" ); document.write( "(x+2) = the third
\n" ); document.write( "and (x+3) = the fourth
\n" ); document.write( "•••••••••••••••••••••••••••••••••••
\n" ); document.write( "x+(x+1)+(x+2)=54+(x+3)
\n" ); document.write( "3x + 3 = 57 + x
\n" ); document.write( "2x = 54
\n" ); document.write( "x=27
\n" ); document.write( "••••••••••••••••••••••••
\n" ); document.write( "The numbers are:
\n" ); document.write( "27,28,29, and 30 \n" ); document.write( "
\n" );