document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1002012>Question 1002012</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Determine whether (-2,3)is a solution of the equation x+3y=11 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #619032 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=619032\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The given point is (-2,3). So, (x,y) = (-2,3) which means x = -2 and y = 3\r<BR>\n" );
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document.write( "Plug in the given x and y values. If we get a true equation, then the ordered pair is a solution. If not, then we don't have a solution.\r<BR>\n" );
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document.write( "x+3y=11\r<BR>\n" );
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document.write( "-2+3*(3)=11 ... plug in x = -2 and y = 3\r<BR>\n" );
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document.write( "-2+9=11\r<BR>\n" );
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document.write( "7 = 11 ... this equation is FALSE\r<BR>\n" );
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document.write( "Since the last equation is FALSE, this means that (-2,3) is NOT a solution to the equation x+3y=11 </SPAN>\n" );
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