document.write( "Question 1001965: Two motorcycles are travelling at speeds of 120 kilometers per hour and 90 kilometers per hour respectively. If the faster one travels for 4 hours longer than the slower one and also goes twice as far, how far did the slow one travel? \n" ); document.write( "
Algebra.Com's Answer #619022 by macston(5194)\"\" \"About 
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\n" ); document.write( "T=time traveled by slower one.
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\n" ); document.write( "(120km/hr)(T+4hrs)=2(90km/hr)(T)
\n" ); document.write( "120T+480=180T
\n" ); document.write( "480=(60T)
\n" ); document.write( "8=T
\n" ); document.write( "The slow one traveled 8 hours.
\n" ); document.write( "(8hrs)(90km/hr)=720km
\n" ); document.write( "ANSWER: The slower bike traveled 720 km
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\n" ); document.write( "CHECK:
\n" ); document.write( "(120km/hr)(T+4hrs)=2(90km/hr)(T)
\n" ); document.write( "(120km/hr)(8hrs+4hrs)=2(90km/hr)(8hrs)
\n" ); document.write( "1440km=2(720km)
\n" ); document.write( "1440km=1440km
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