document.write( "Question 1001965: Two motorcycles are travelling at speeds of 120 kilometers per hour and 90 kilometers per hour respectively. If the faster one travels for 4 hours longer than the slower one and also goes twice as far, how far did the slow one travel? \n" ); document.write( "
Algebra.Com's Answer #619022 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "T=time traveled by slower one. \n" ); document.write( ". \n" ); document.write( "(120km/hr)(T+4hrs)=2(90km/hr)(T) \n" ); document.write( "120T+480=180T \n" ); document.write( "480=(60T) \n" ); document.write( "8=T \n" ); document.write( "The slow one traveled 8 hours. \n" ); document.write( "(8hrs)(90km/hr)=720km \n" ); document.write( "ANSWER: The slower bike traveled 720 km \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "(120km/hr)(T+4hrs)=2(90km/hr)(T) \n" ); document.write( "(120km/hr)(8hrs+4hrs)=2(90km/hr)(8hrs) \n" ); document.write( "1440km=2(720km) \n" ); document.write( "1440km=1440km \n" ); document.write( " \n" ); document.write( " |