document.write( "Question 1001918: Tyler has two savings accounts that his grandparents opened for him. One of the accounts pay 6% annual interest, whereas the other pays 8% annual interest. If you have $800 more invested at 8% than you invested at 6%, how much do you have invested in each account if the total amount of interest you earn in a year is $120?\r
\n" ); document.write( "\n" ); document.write( "Just need to know how to set up the problems
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Algebra.Com's Answer #619018 by macston(5194)\"\" \"About 
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\n" ); document.write( "S = amount at 6%; E = amount at 8% = S+$800
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\n" ); document.write( "0.06S + 0.08E = $120
\n" ); document.write( "That is all you need to know to set it up.
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\n" ); document.write( "The following is given in case you have trouble:
\n" ); document.write( "0.06S + (0.08)(S+$800)=$120
\n" ); document.write( "0.06S+0.08S+$64=$120
\n" ); document.write( "0.14S=$56
\n" ); document.write( "S=$400
\n" ); document.write( "ANSWER 1: You have $400 in the 6% account.
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\n" ); document.write( "E=S+$800=$400+$800=$1200
\n" ); document.write( "ANSWER 2: You have $1200 in the 8% account.
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\n" ); document.write( "CHECK:
\n" ); document.write( "0.06S+0.08E=$120
\n" ); document.write( "0.06($400)+0.08($1200)=$120
\n" ); document.write( "$24+$96=$120
\n" ); document.write( "$120=$120
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