document.write( "Question 1001916: The length of a rectangle is 5 inches less than 4 times the width. The perimeter is 100 inches. Find the length and the width.\r
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\n" ); document.write( "\n" ); document.write( "I would just like to know how to write this equation out and then I can take it from there just need an exaMPLE, pLEASE
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Algebra.Com's Answer #618975 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
perimeter = 2 * length + 2 * width
\n" ); document.write( "100 = 2 * length + 2 * width\r
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\n" ); document.write( "\n" ); document.write( "the length of the rectangle is 5 inches (or centimeters0 less than 4 times the width.
\n" ); document.write( "you get length = 4 * width - 5\r
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\n" ); document.write( "\n" ); document.write( "4 * width has to be greater than 5, otherwise length will be negative or 0.\r
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\n" ); document.write( "\n" ); document.write( "when width = 6, length = 4*6-5 = 24-5 = 19
\n" ); document.write( "when width = 10, length = 4*10-5 = 40-5 = 35
\n" ); document.write( "etc.\r
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\n" ); document.write( "\n" ); document.write( "now that you have solved for the length in terms of the width, you can replace length in the equation with 4 * width - 5 to get:\r
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\n" ); document.write( "\n" ); document.write( "100 = 2 * (4 * width - 5) + 2 * width\r
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\n" ); document.write( "\n" ); document.write( "simplify that to get:\r
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\n" ); document.write( "\n" ); document.write( "100 = 8 * width - 10 + 2 * width.\r
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\n" ); document.write( "\n" ); document.write( "combine like terms to get:\r
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\n" ); document.write( "\n" ); document.write( "100 = 10 * width - 10\r
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\n" ); document.write( "\n" ); document.write( "you can solve for width and, once you know that, you can solve for length.\r
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\n" ); document.write( "\n" ); document.write( "you can use variable names to represent the length and the width.\r
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\n" ); document.write( "\n" ); document.write( "when you do that, you will get something like the following.\r
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\n" ); document.write( "\n" ); document.write( "perimeter = 2 * length + 2 * width
\n" ); document.write( "let x = length and y = width.
\n" ); document.write( "equation becomes perimeter = 2x + 2y
\n" ); document.write( "since perimeter = 100, equation becomes:
\n" ); document.write( "100 = 2x + 2y\r
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\n" ); document.write( "\n" ); document.write( "you are given the length is 5 less than 4 times the width.
\n" ); document.write( "you get x = 4y - 5\r
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\n" ); document.write( "\n" ); document.write( "in the equation of 100 = 2x + 2y, replace x with 4y - 5 to get:
\n" ); document.write( "100 = 2 * (4y-5) + 2y = 8y - 10 + 2y = 10y - 10\r
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\n" ); document.write( "\n" ); document.write( "your equation is 100 = 10y - 10
\n" ); document.write( "y is the width\r
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\n" ); document.write( "\n" ); document.write( "after you solve for y you can then use that value of y to solve for x.\r
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\n" ); document.write( "\n" ); document.write( "same answer except now you are using x and y instead of length and width.
\n" ); document.write( "they both represent the same thing.\r
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\n" ); document.write( "\n" ); document.write( "if you do this correctly, your answer should be:\r
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\n" ); document.write( "\n" ); document.write( "length = 39
\n" ); document.write( "width = 11\r
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\n" ); document.write( "\n" ); document.write( "length is 5 less than 4 times width when width = 11 becomes length = 5 less than 44 which becomes length = 39\r
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\n" ); document.write( "\n" ); document.write( "100 = 2 * length + 2 * width becomes:
\n" ); document.write( "100 = 2*39 + 2*11 which becomes:
\n" ); document.write( "100 = 78 + 22 which becomes:
\n" ); document.write( "100 = 100\r
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\n" ); document.write( "\n" ); document.write( "this confirms the solution is correct.\r
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