document.write( "Question 1001891: five year ago the average age of A.B.C and D was 45 year. with E joining them . the average of all the five is 49 year .the age E is. \n" ); document.write( "
Algebra.Com's Answer #618966 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! five year ago the average age of A.B.C and D was 45 year. \n" ); document.write( "Find the total of their ages five years ago \n" ); document.write( "45 * 4 = 180 \n" ); document.write( ": \n" ); document.write( " with E joining them . the average of all the five is 49 year .the age E is. \n" ); document.write( "All 4 of them aged 5 yrs, therefore, their total increased by 20 yrs \n" ); document.write( "Now the their total ages is 200 \n" ); document.write( " \n" ); document.write( "200 + E = 5(49) \n" ); document.write( "E = 245 - 200 \n" ); document.write( "E = 45 yrs old \n" ); document.write( " |