document.write( "Question 1001891: five year ago the average age of A.B.C and D was 45 year. with E joining them . the average of all the five is 49 year .the age E is. \n" ); document.write( "
Algebra.Com's Answer #618966 by ankor@dixie-net.com(22740)\"\" \"About 
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five year ago the average age of A.B.C and D was 45 year.
\n" ); document.write( "Find the total of their ages five years ago
\n" ); document.write( "45 * 4 = 180
\n" ); document.write( ":
\n" ); document.write( " with E joining them . the average of all the five is 49 year .the age E is.
\n" ); document.write( "All 4 of them aged 5 yrs, therefore, their total increased by 20 yrs
\n" ); document.write( "Now the their total ages is 200
\n" ); document.write( "\"%28%28200%2BE%29%29%2F5\" = 49
\n" ); document.write( "200 + E = 5(49)
\n" ); document.write( "E = 245 - 200
\n" ); document.write( "E = 45 yrs old
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