document.write( "Question 1001880: Each side of rhombus 10 cm long of its diagonal measure 16 cm find the length of other diagonal and hence find the area of rhombus \n" ); document.write( "
Algebra.Com's Answer #618947 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The diagonals of a rhombus are perpendicular, hence the two diagonals and the sides of the rhombus create four congruent right triangles where each side of the rhombus is the hypotenuse of one of the triangles. Since you have sides of 10 (hypotenuse) and one-half of a diagonal is 8 (one leg), you can calculate the measure of one-half of the other diagonal using Pythagoras (or by recognizing a 3-4-5 right triangle). The area is the half of one diagonal times half of the other diagonal times 2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it\r \n" ); document.write( "\n" ); document.write( " |