document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1001817>Question 1001817</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Philip jogged from his house to a park at an average rate of 12mph where he met his friend Julia.  Julia then drove him home at an average rate of 35mph.  If the whole trip took 3 hours, how far is it from Philip's house to the park? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #618908 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=618908\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> jogging rate = 12 mph<BR>\n" );
document.write( "distance be x\r<BR>\n" );
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document.write( "time jogging = x/12\r<BR>\n" );
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document.write( "car speed = 35 mph<BR>\n" );
document.write( "time return by car = x/35\r<BR>\n" );
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document.write( "x/12 + x/35 = 3\r<BR>\n" );
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document.write( "(35x+12x)/12*35 = 3\r<BR>\n" );
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document.write( "47x = 3*12*35\r<BR>\n" );
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document.write( "x = 3*12*35/47\r<BR>\n" );
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document.write( "x= 26.8 miles\r<BR>\n" );
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document.write( " </SPAN>\n" );
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