document.write( "Question 1001845: The sum of the digits of a two two-digit number is 13. If the digits are reversed, the new number is 27 less than the original number. Find the number.\r
\n" ); document.write( "\n" ); document.write( "Choices:
\n" ); document.write( "76
\n" ); document.write( "94
\n" ); document.write( "95
\n" ); document.write( "85
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Algebra.Com's Answer #618906 by mananth(16946)\"\" \"About 
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x in the tens place
\n" ); document.write( "y in the digits place\r
\n" ); document.write( "\n" ); document.write( " the number be 10x+y\r
\n" ); document.write( "\n" ); document.write( "x+y =13\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "reversed number = 10y+x\r
\n" ); document.write( "\n" ); document.write( "10y+x = 10x+y -27\r
\n" ); document.write( "\n" ); document.write( "9y-9x=-27\r
\n" ); document.write( "\n" ); document.write( "/9\r
\n" ); document.write( "\n" ); document.write( "y-x=-3\r
\n" ); document.write( "\n" ); document.write( "add the two equations
\n" ); document.write( "2y = 10
\n" ); document.write( "/2
\n" ); document.write( "y=5\r
\n" ); document.write( "\n" ); document.write( "x+y=13\r
\n" ); document.write( "\n" ); document.write( "y=5
\n" ); document.write( "x=8\r
\n" ); document.write( "\n" ); document.write( "85 is the number\r
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