document.write( "Question 1001762: cos^2x*tanx+sin^2x*tanx
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document.write( " sinx\r
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document.write( "cosine squared (x) times tan (x) plus sin squared (x) times tan (x) all divided by sin (x) \n" );
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Algebra.Com's Answer #618861 by Boreal(15235) You can put this solution on YOUR website! cos^2x*tan x+ sin^2 x + tan x= \n" ); document.write( "tan x( cos^2 x+sin^2 x). But cos^2 x+ sin^2 x=1 \n" ); document.write( "all divided by sinx \n" ); document.write( "tan x/sin x \n" ); document.write( "but tan x =sin x/ cos x\r \n" ); document.write( "\n" ); document.write( "(sinx /cos x) divided by sin x \n" ); document.write( "=1/cos x= \n" ); document.write( "sec x. \n" ); document.write( " |