document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=85679>Question 85679</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help. I am stuck on this problem. I have a partial solution I think but I am not understanding how to do this. Could you please explain what I am supposed to be substituting in this problem and help me find the answer -if independent, inconsistent, or dependent><BR>\n" );
document.write( "x-y=3<BR>\n" );
document.write( "3x-2y=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #61886 by </B><A HREF=/tutors/aboutme.mpl?userid=scianci><B>scianci(186)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scianci><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=61886\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Note that the slopes of these equations are 1 and 3/2. Since they are different, the system is independent. Use a linear combination to solve for one of the variables:\r<BR>\n" );
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document.write( "2(x - y = 3)  -->  2x - 2y =  6<BR>\n" );
document.write( "3x - 2y = 3   --> -3x + 2y = -3\r<BR>\n" );
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document.write( "-x = -3<BR>\n" );
document.write( "x = 3\r<BR>\n" );
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document.write( "(3) - y = 3  [using the 1st. equation]<BR>\n" );
document.write( "y = 0<BR>\n" );
document.write( "Solution is (3 , 0) </SPAN>\n" );
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