document.write( "Question 1001675: Please help and show all steps and work.Thanks\r
\n" ); document.write( "\n" ); document.write( "A chemist has three different acid solutions. The first acid solution contains 20% acid, the second contains 30% and the third contains 75%. He wants to use all three solutions to obtain a mixture of 64 liters containing 50% acid, using 2 times as much of the 75% solution as the 30% solution. How many liters of each solution should be used?\r
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\n" ); document.write( "\n" ); document.write( "My answers I came up with is 34,65,29.2
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Algebra.Com's Answer #618758 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Variables x, y, z for low, medium, high conc. materials.\r
\n" ); document.write( "\n" ); document.write( "\"system%28x%2By%2Bz=64%2Cz%2Fy=2%2C%2820x%2B30y%2B75z%29%2F64=50%29\"
\n" ); document.write( "Simplify the system to something convenient or comfortable.
\n" ); document.write( "\"system%28x%2By%2Bz=64%2Cz=2y%2C4x%2B6y%2B15z=640%29\"\r
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\n" ); document.write( "\n" ); document.write( "Obvious substitution for z.
\n" ); document.write( "\"highlight%28system%28x%2B2y=64%2Cx%2B36y=640%29%29\"
\n" ); document.write( "Using elimination subtracting the '640' equation from the '64' equation,
\n" ); document.write( "\"highlight_green%28y=288%2F17=highlight%2816.94%2Aliters%29%29\" for the 30% material.\r
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\n" ); document.write( "\n" ); document.write( "You can determine x for the 20% material and the z for the 75% material yourself.
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