document.write( "Question 1001675: Please help and show all steps and work.Thanks\r
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document.write( "A chemist has three different acid solutions. The first acid solution contains 20% acid, the second contains 30% and the third contains 75%. He wants to use all three solutions to obtain a mixture of 64 liters containing 50% acid, using 2 times as much of the 75% solution as the 30% solution. How many liters of each solution should be used?\r
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document.write( "My answers I came up with is 34,65,29.2 \n" );
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Algebra.Com's Answer #618758 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! Variables x, y, z for low, medium, high conc. materials.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Simplify the system to something convenient or comfortable. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Obvious substitution for z. \n" ); document.write( " \n" ); document.write( "Using elimination subtracting the '640' equation from the '64' equation, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can determine x for the 20% material and the z for the 75% material yourself. \n" ); document.write( " \n" ); document.write( " |