document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1001642>Question 1001642</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the distance from town A to town B is 18 miles. Luke starts his journey from town A and travels 1/6 of the total distance. How much further does he have to travel in order to reach town B.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #618751 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=618751\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "d=total distance from A to B<BR>\n" );
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document.write( "Distance traveled=(1/6)d<BR>\n" );
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document.write( "Distance remaining=total distance - distance traveled<BR>\n" );
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document.write( "Distance remaining=d-(1/6)d<BR>\n" );
document.write( "Distance remaining= (6/6)d-(1/6)d=(5/6)d<BR>\n" );
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document.write( "d=18 mi<BR>\n" );
document.write( "(5/6)d=(5/6)18mi=(90/6)mi=15mi<BR>\n" );
document.write( "ANSWER: He has 15 miles remaining. </SPAN>\n" );
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