document.write( "Question 1001623: Tom is 4 times as old as Todd. In 5 years Tom's age will be 1 year less than 3 times as old as Todd. How old is Tom?\r
\n" ); document.write( "\n" ); document.write( "My work so far:
\n" ); document.write( "I have been working on the problems for this question and I figured out that 4x is what Tom would be and I was looking at a previous question and was confused as to how the particular numbers are plugged in. I was working for a while too.
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Algebra.Com's Answer #618735 by macston(5194)\"\" \"About 
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\n" ); document.write( "D=Todd's age; M=Tom's age=4D
\n" ); document.write( "In 5 years, Todd age= D+5
\n" ); document.write( "In 5 years, Tom's age=M+5
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\n" ); document.write( "(M+5)-1=3(D+5) Substitute for M (M=4D)
\n" ); document.write( "4D+5-1=3D+15
\n" ); document.write( "4D+4=3D+15
\n" ); document.write( "D=11
\n" ); document.write( "ANSWER 1: Todd is eleven years old.
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\n" ); document.write( "M=4D=4(11)=44
\n" ); document.write( "ANSWER 2: Tom is 44 years old.
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\n" ); document.write( "CHECK:
\n" ); document.write( "(M+5)-1=3(D+5)
\n" ); document.write( "(44+5)-1=3(11+5)
\n" ); document.write( "49-1=3(16)
\n" ); document.write( "48=48
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