document.write( "Question 1001512: A square poster has sides measuring 2 feet less than the sides of a square sign if the difference between their areas is 12 square feet find the lengths of the sides of the poster and sign \n" ); document.write( "
Algebra.Com's Answer #618734 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A square poster has sides measuring 2 feet less than the sides of a square sign \n" ); document.write( " if the difference between their areas is 12 square feet find the lengths of the sides of the poster and sign \n" ); document.write( ": \n" ); document.write( "let x = the side of the poster \n" ); document.write( "then \n" ); document.write( "(x+2) = the side of the sign \n" ); document.write( ": \n" ); document.write( "Sign area - poster area = 12 \n" ); document.write( "(x+2)^2 - x^2 = 12 \n" ); document.write( "FOIL(x+2)(x+2) \n" ); document.write( "x^2 + 2x + 2x + 4 - x^2 = 12 \n" ); document.write( "combine like terms \n" ); document.write( "4x + 4 = 12 \n" ); document.write( "4x = 12 - 4 \n" ); document.write( "4x = 8 \n" ); document.write( "x = 8/4 \n" ); document.write( "x = 2 ft is the side of the poster, then 4 ft is the side of the sign \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this \n" ); document.write( "4^2 - 2^2 = \n" ); document.write( "16 - 4 = 12 \n" ); document.write( " \n" ); document.write( " |